获取数组中的下一个值

Question

I have this array:

<?php
$arrFiles = array_diff(scandir("scans", 0), array(".", ".."));
$arrFiles = array_values($arrFiles);
?>

that prints fine with this:

<?php 
print_r(array_values($arrFiles));
?>

and these buttons that I want to use to skip from one image to the prev or next:

  <a href="javascript:skipLeft()"><img src="/ico/skip_left.gif" width="12" height="12" hspace="1" vspace="1" />skip left</a> / 
  <a href="javascript:skipRight()"><img src="/ico/skip_right.gif" width="12" height="12" hspace="1" vspace="1" />skip right</a>

I probably need some kind of loop, -1 and +1 or prev and next or something.

I've tried so many things. No luck.

Page: http://flamencopeko.net/songs_scans_skip.php

Source: http://flamencopeko.net/songs_scans_skip.txt

Answer 1

You will probably want a loop like this:

for($i=0; $i < sizeof($arrFiles); $i++)
{
  echo "<img src=scans/" . $arrFiles[$i] . ">";
}

to select an image using a page by page technique you could use this:

if($_GET['p'] >= sizeof($arrFiles)) echo "<img src=scans/" . $arrFiles[sizeof($arrFiles)] . ">";
else{
  echo "<img src=scans/" . $arrFiles[$_GET['p']] . ">";
}

use this for links/buttons

echo "<a href='yourpagename.php?p=" . $_GET['p']+1 . "'>"; // next
echo "<a href='yourpagename.php?p=" . $_GET['p']-1 . "'>"; // previous

you can use the same if as above to filter out max of array size and obviously use 0 as min array size to cover the low end

if(!max){ //shownext }
if(!min){ //showprevious }

note this is not going to work without proper structuring but you can get the idea