douzi1117 2013-01-03 09:11
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在PHP中获取参数值作为参考[重复]

Possible Duplicate:
How can arguments to variadic functions be passed by reference in PHP?

I need to get the values from the arguments of a method or function. I know i can do this with func_get_args(). But i really need to get the arguments by reference. Is there any way to do that?

I currently have this:

<?php
class Test
{
    function someFunc ( $arg1, $arg2 )
    {
        print_r ( func_get_args() );
    }
}

$t = new Test();
$t->someFunc('a1', 'a2');
?>

In my real code the argument values are passed to another class->method(). In there i want to be able to change the argument values. This would be possible if i could get the values as reference.

Is there a solution for this?

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2条回答 默认 最新

  • duanlongnao0028 2013-01-03 09:20
    关注

    Nothing stopping you now .. just make it a variable instead if not PHP would return Fatal error: Cannot pass parameter 1 by reference

    class Test {
    
        function someFunc(&$arg1, &$arg2) {
            var_dump(func_get_args());
    
            $arg1 = strtoupper($arg1);
            $arg2 = strtoupper($arg2);
        }
    }
    
    echo "<pre>";
    
    $arg1 = "a1";
    $arg2 = "ar2";
    $t = new Test();
    $t->someFunc($arg1, $arg2);
    
    var_dump($arg1, $arg2);
    

    Output

    array (size=2)
      0 => string 'a1' (length=2)
      1 => string 'ar2' (length=3)
    
    string 'A1' (length=2) // modified
    string 'AR2' (length=3) // modified
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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