获取多个查询结果并使用带有oracle的php显示到表中

Question

My issue is I have a website that is linking to multiple tables in Oracle. I currently have PHP code that checks user input assigned to a variable to find data in a table, then the oci_fetch_row statement that grabs the row where the data matches. This works fine but I cannot find how to output more than one row from a table if some values are the same?

Currently the one row it grabs is put into a simple HTML table.

Any help in to how to fetch all rows that the data matches and output to table would be appreciated.

My code is:

$userfeedback = "SELECT * FROM ASSET_FEEDBACK WHERE USER_EMAIL = '$userEmail' ORDER BY FEEDBACK_DATE";

$stmt3 = oci_parse($conn, $userfeedback);

if(oci_execute($stmt3))

{


    $row=oci_fetch_row($stmt3) ;

    print"<h2 id='title'>This Users Feedback</h2>";
    "<table border='2'>";

    print"<tr><td><p>Feedback ID:</td><td>$row[0]</td></tr>";
    print"<tr><td>Asset ID:</td><td>$row[1]</td></tr>";
    print"<tr><td>Feedback:</td><td>$row[3]</td></tr>";
    print"<tr><td>Date added:</td><td>$row[4]</td></tr>";

    print"</table></br>";   

}

Answer 1

Put the oci_fetch_row statement into a while loop. OCI Fetch Array for a code sample

print"<h2 id='title'>This Users Feedback</h2>";
print"<table border='2'>";

while ($row=oci_fetch_row($stmt3))
{

    print"<tr><td><p>Feedback ID:</td><td>$row[0]</td></tr>";
    print"<tr><td>Asset ID:</td><td>$row[1]</td></tr>";
    print"<tr><td>Feedback:</td><td>$row[3]</td></tr>";
    print"<tr><td>Date added:</td><td>$row[4]</td></tr>";


}
print"</table></br>";