鼠标移动至少一次时创建PHP会话

Question

I want to create php session when mouse is moved at least once then no need to do anything if mouse keeps moving

I am using this code but its not solving the requirement

<script type="text/javascript">
jQuery(document).ready(function()
{
   $(document).mousemove(function(e)
   {
      $('#status').html(e.pageX);
      $('#status1').html(e.pageY);
      $.ajax({
        type: 'POST',
        url: 'second.php',
        data: { 
            'x': '10', 
            'y': '20' 
        },
        success: function(msg){
            //what you want after request
        }
    });
  });
  });
</script>

</div>

Answer 1

The PHP code should be something like this:

session_start();
if (!isset($_SESSION['mouseMoved'])
    $_SESSION['mouseMoved'] = "whatever you want";

Also, you should set some variable in JS so that the request is only sent to the server once.

Updated: a working jsfiddle https://jsfiddle.net/bqh0yrtp/