douchui1488 2013-11-23 16:14
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简单的代码不工作[关闭]

Hello guys I want to show the database on my website using this code which is given below but it's giving me annoying error again and again. I have tried everything but nothing is working it give me same error notice

Here is the error Notice

Notice: Undefined index: name in C:\xampp\htdocs\test3\index.php on line 15

Here is the PHP Code

<?php
$connect = mysql_connect("localhost","root","123");

if(!$connect) {
    die("Failed to Connect: " . mysql_error());
    }
    if (!mysql_select_db ("login")){
        die("Failed to Select DB: ". mysql_error());
    }

    $results = mysql_query ("Select * from users ");

    while($row = mysql_fetch_array($results)){
        echo $row['name'];
    }
?>

I have also tried to replace mysql_fetch_array($results) with this mysqli_fetch_assoc($result) and it's also not working please run this code yourself and then give me that code. Thanks

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4条回答 默认 最新

  • duanmeng9336 2013-11-23 16:43
    关注

    You can also simply do it this way to avoid confusion on the if's

    mysql_connect("localhost","root","123") or die("Failed to Connect");

    mysql_select_db ("login") or die ("cannot connect to db");

    $results = mysql_query ("Select * from users ");

    while($row = mysql_fetch_assoc($results))

    {
     echo $row['name'];
    }
    

    Since the error refers to the name, you might want to check your users table if the column name exists.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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