dsmvqp3124 2018-05-12 14:27
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使用PHP变量HTML嵌入视频不起作用

I'm trying to display all videos a webpage using the following code, I've gotten as far as being able to iterate over the files, printing the file names and embedding a video. However the videos are greyed out and don't work, I suspect I did something wrong with using $filename in the code.

<?php
$dir = new DirectoryIterator(dirname(__FILE__));
foreach ($dir as $filename) {
    if (!$filename->isDot()) {

        if ($filename != "index.php" and $filename != "error_log") {

            echo $filename, "<br>"; 

            echo '<video width="400" controls="controls" preload="metadata">
            <source src=$filename type="video/mp4"></video>';

            echo "<br><br>";
        }

    }
}
?>

This is how it shows up:

enter image description here

enter image description here

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3条回答 默认 最新

  • droxy80248 2018-05-12 14:31
    关注

    Hi

    You are echo $filename like a string, not a PHP variable.

    Remember, if echo with single quotes ' all inside it will echo like string and echo with double quotes " will echo PHP variables reading their value. Informations about strings in PHP are nicley explained e.g. here .

    You can change your piece of code witch echo HTML video to:

    echo '<video width="400" controls="controls" preload="metadata"><source src="' . $filename . '" type="video/mp4"></video>';
    

    Note that there were also missing double quotes for HTML video tag src property and I added them in code above.

    Cheers

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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