解析错误：语法错误，意外']'[关闭]

Question

I'm getting this error:

Parse error: syntax error, unexpected ']', expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in your code on line 70

Line 70 is $message.

$random_keys=array_rand($lel,1);
$message[] = $lel[$random_keys[0]];

The whole code is here:

$message = array(); 
$lel = array(
    'Are you sure its the new year?', 
    'And i thought i was dumb', 'its not new year yet', 
    'LOL its ${date}', '...', '.....', '...', 'WUT', '.......', 
    'Ya drunk bruh ?', 'You sure you are not drunk ? what is 1+1 then ?'
);
$random_keys=array_rand($lel,1);
$message[] = $lel[$random_keys[0]];

Can we do it like this?

$message[] = $lel[rand(1,11)];

It still gives:

Parse error: syntax error, unexpected ']', expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING)

Answer 1

You are only picking one random key here:

$random_keys=array_rand($lel,1);

So you want to do this:

$random_key = array_rand($lel,1);
$message[] = $lel[$random_key];

Working example: http://3v4l.org/PHWD8

Though, since you're only picking one random key, and one random message, do you even need $message to be an array? I'd just do this:

$message = $lel[array_rand($lel)];

Working example: http://3v4l.org/jJKrG

As for your parse error, there's something we're not seeing in the code you posted. Perhaps it is some other surrounding code, or perhaps you modified the code before pasting here? In any event, you can see that your exact code does not produce a parse error: http://3v4l.org/Io1jc