PHP正则表达式允许特殊字符，但没有任何空格

Question

I have the following Regex to allow alphanumeric characters and following special characters

/()-

The Regular expression is

/[^A-Za-z0-9-()-/]/

The complete method is

public function ValidateNumber($number)
{
    $return = true;
    $matches = null;
    if((preg_match('/[^A-Za-z0-9-/()-]/', $number, $matches)) > 0)
    {
       $return = false; 
    }
    return $return;
}

Above method woks fine, but also return TRUE if number has space. When i remove '/' from Regex then if number has 'space' in it then it returns FALSE.

So seems some issue with '/' in Regex.

Please advise some solution

Answer 1

Regex to allow alphanumeric characters and the the above mentioned special characters /()-,

^[A-Za-z0-9()\/-]+$

^ inside(at the strat of) chracter class means not. So your regex allows any character not of the ones mentioned inside the character class. And also it's better to escape / inside the character class and always consider in putting - at the start or end of the character class. To allow one ore more characters which was mentioned inside char class then you need to add + after the character class.

Explanation:

^                        the beginning of the string
[A-Za-z0-9()\/-]+        any character of: 'A' to 'Z', 'a' to 'z',
                         '0' to '9', '(', ')', '\/', '-' (1 or more
                         times)
$                        before an optional 
, and the end of the
                         string