带有int或float to number的PHP字符串

Question

If I have two strings in an array:

$x = array("int(100)", "float(2.1)");

is there a simple way of reading each value as the number stored inside as a number?

The reason is I am looking at a function (not mine) that sometimes receives an int and sometimes a float. I cannot control the data it receives.

function convertAlpha($AlphaValue) { 
    return((127/100)*(100-$AlphaValue));
}

It causes an error in php

PHP Notice: A non well formed numeric value encountered

which I want to get rid of.

I could strip the string down and see what it is and do an intval/floatval but wondered if there was a neat way.

UPDATE:

Playing about a bit I have this:

function convertAlpha($AlphaValue) {

$x = explode("(", $AlphaValue);
$y = explode(")", $x[1]);

if ($x[0] == "int") {
    $z = intval($y[0]);
}

if ($x[0] == "float") {
    $z = floatval($y[0]);
}

return((127/100)*(100-$z)); }

This which works but it just messy.

Answer 1

<?php

$x = array("int(100)", "float(2.1)");

$result = [];

foreach($x as $each_value){
    $matches = [];
    if(preg_match('/^([a-z]+)(\((\d+(\.\d+)?)\))$/',$each_value,$matches)){
        switch($matches[1]){
          case "int": $result[] = intval($matches[3]); break;
          case "float": $result[] = floatval($matches[3]);
        }
    }
}

print_r($result);

OUTPUT

Array
(
    [0] => 100
    [1] => 2.1
)