So I have a route defined in my web.php, like so....
Route::any('/items/{id}/{slug}', 'Items\ItemController@item')->name('items.item');
I am trying to make a function where I can get the string pattern for the URL, '/items/{id}/{slug}' from the route by calling it's name...
I assumed this would work.. but it doesn't (it tells me I'm missing the parameters id and slug).
// Should assign the string 'items/{id}/{slug}' to the variable.
$url_pattern = route('items.item');
I'm using Laravel 5.3.
所以我在web.php中定义了一条路线，就像这样....
Route :: any（'/ items / {id} / {slug}'，'Items \ ItemController @ item'） - ＆gt; name（'items.item'）;
我正在尝试创建一个函数，我可以通过调用它的名称从URL获取URL的'/ items / {id} / {slug}'的字符串模式 ...
我认为这样可行..但它没有（它告诉我我缺少参数id和slug）。
< pre> //应该将字符串'items / {id} / {slug}'分配给变量。
$ url_pattern = route（'items.item'）;
我正在使用Laravel 5.3。
You can access the Route's uri as follows:
微信扫一扫$url_pattern = app('router')->getRoutes()->getByName('items.item')->uri;
var_dump($url_pattern);
// will return:
// "items/{id}/{slug}"
You can always create a faux route. When you are invoking route(), one has to assume you know the params it expects.
If you would like to get it as a string (to be used in JS for example), just pass the names of the params as the params. For example:
$url_pattern = route('items.item', ['id' => '{id}', 'slug' => '{slug}']);
// will generate:
// items/{id}/{slug}