duanfen9983 2016-02-20 05:15
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在Web网址中传递凭据时无法登录

Creating a user login, when I use username and password within PHP file then, I am getting Done as user exists. Which is GOOD

<?php

    .....

    /*** for sample */
    // $_POST["username"] = "sun";
    // $_POST["password"] = "live";

    $username = $_POST['username'];
    $password = $_POST['password'];

    $strSQL = "select * from test_users where username = '".$username."' and  password = '".$password."' ";

    $objQuery = mysql_query($strSQL);
    $intNumRows = mysql_num_rows($objQuery);

    if($intNumRows==0)
    {
    echo "Not Done" ;
    }
    else
    {
    echo "Done" ;
    }

    mysql_close($objConnect);
?>

But, when I pass these values in web url, I am always getting, Not Done as message. WHY

 http://mydomain.info/retrofit_user/login.php?username=sun&&password=live
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  • doucong4535 2016-02-20 05:30
    关注

    You have to ampersands in your query strings, that's an issue.

    login.php?username=sun&&password=live
    

    Not to mention that POST and GET are different method.

    You can use $_REQUEST two access both.

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