使用带有php的构造函数更改变量

Question

Why does the constructor not change the name of the variable? It tells me $name is not defined.

<?php
class Person{
public $name;
  public function __construct($var){
  $this->name = $var;
  }
  public function greet(){
  echo "Hello, my name is ".$name.", nice to meet you :-)";
  }
}
$me = new Person("Bob");
$me->greet();
?>

Thanks in advance :-)

Stephen,

Answer 1

You just use $this when access accessing class members in side of your methods, just like you did inside of your constructor:

echo "Hello, my name is ".$this->name.", nice to meet you :-)";