drnl10253 2015-10-18 20:02
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使用带有php的构造函数更改变量

Why does the constructor not change the name of the variable? It tells me $name is not defined.

<?php
class Person{
public $name;
  public function __construct($var){
  $this->name = $var;
  }
  public function greet(){
  echo "Hello, my name is ".$name.", nice to meet you :-)";
  }
}
$me = new Person("Bob");
$me->greet();
?>

Thanks in advance :-)

Stephen,

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1条回答 默认 最新

  • doufu1950 2015-10-18 20:03
    关注

    You just use $this when access accessing class members in side of your methods, just like you did inside of your constructor:

    echo "Hello, my name is ".$this->name.", nice to meet you :-)";
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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