doushang1880 2015-08-10 09:47
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显示带数据库值的复选框

I am having trouble with a part of my code. I want the checkbox in the last column to be checked if the corresponding DB value is 1, but something keeps going wrong with my code, anyone who sees what's wrong? It's probably very simple but I can't find it.

<?php
    $sql = "SELECT * FROM registered ORDER BY datum"; 
$myData=mysql_query($sql,$con) ;
?>

<table width="1100" border="1">
<tr>
<th style="text-align:center; padding:0 10px">naam</th>
<th style="text-align:center; padding:0 10px">betaald?</b></th>
</tr>

<?php

$betaald = $record['betaald'];

while($record = mysql_fetch_array($myData)) {

    echo  "<tr>";
    echo  "<td>" . $record['naam'] . "</td>";
    echo  "<td> <input type='checkbox' name='betaald' id='betaald' value='1' ". echo ($betaald==1 ? 'checked' : ''); . " ></td>";
    echo  "</tr>";

    }

mysql_close($con);
?>
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4条回答 默认 最新

  • dongsi2317 2015-08-10 09:53
    关注
    <?php
    $sql = "SELECT * FROM registered ORDER BY datum";
    $myData = mysql_query($sql, $con);
    ?>
    
    <table width="1100" border="1">
        <tr>
            <th style="text-align:center; padding:0 10px">naam</th>
            <th style="text-align:center; padding:0 10px">betaald?</b></th>
        </tr>
    
        <?php while ($record = mysql_fetch_array($myData)) { ?>
    
            <tr>
                <td><?php echo $record['naam'] ?></td>
                <td> 
                    <input type='checkbox' name='betaald' id='betaald' value='1'
                            <?php if($record['betaald'] == 1){ ?>
                                checked="checked"
                            <?php } ?>
                            />
                </td>
            </tr>
       <?php  } ?>
    </table>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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