强制file_get_contents（）不要将php代码呈现为纯文本

Question

How can I get expected output from example below?

Note: I'm using $content = file_get_contents('content.php'); to use content where and when possible so it is not a direct output on screen. include() breaks the pages.

content.php

<p>Hello <?php echo 'World!'; ?></p>

reader.php

<b>Message from another file:</b> <?php echo file_get_contents('content.php'); ?>

Output of code above is:

Message from another file: Hello <?php echo 'World!'; ?>

Instead of (expected):

Message from another file: Hello World!

Answer 1

I think you are looking for <?php include('content.php');

file_get_contents — Reads entire file into a string

PHP.net file_get_contents - manual

The include statement includes and evaluates the specified file.

PHP.net include - manual

Try making content.php into a file that has a function that returns the content you want (you may want to have parameters). Simply require the file then call the function and save the output.

Example:

content.php

function get_content($world){
  return '<p>Hello ' . $world . '</p>';
}

reader.php

<?php 
require('content.php');
$content = get_content('world');
?>
<b>Message from another file:</b> <?php echo $content; ?>