检查数组中的索引是否不同[关闭]

Question

I am trying to compare indexes in one array, if all indexes are not the same then It should dispay error. If they are same, take one value as string.

First I retrieve data from db,

$idNaloga = array();

 while($r=$ss->fetch()){
   $idNaloga[] = $r['idNaloga'];
 }

If I receive array like this, it should display error because of 72

array(3) {
  [0]=>
  string(2) "19"
  [1]=>
  string(2) "19"
  [2]=>
  string(2) "72"
}

If result is, it should take 19 as string.

array(4) {
  [0]=>
  string(2) "19"
  [1]=>
  string(2) "19"
  [2]=>
  string(2) "19"
  [3]=>
  string(2) "19"
}

I was trying to use array_unique() function, but could not get correct result. I was googling but could not find it.

Answer 1

You can do this with array_unique

if (count(array_unique($idNaloga)) > 1) {
     //return error
} else {
    echo $idNaloga[0];
}