doukong5394 2018-04-12 20:29
浏览 62
已采纳

在PHP中任意对数组中的对象进行排序

I have a function that is looping over a bunch of items that each look something like this:

[
{"Target":"col-one","Value":0.261},
{"Target":"col-two","Value":0.881},
{"Target":"col-three","Value":0.571},
{"Target":"col-four","Value":0}
]

I would like to re-order each item so that instead of going in ascending order, it goes something like col-one, col-four, col-three, col-two. Is there a relatively simple method that can accomplish this type of arbitrary sorting?

To be clear, I want the result to look like the following:

[
     {"Target":"col-one","Value":0.261}, 
     {"Target":"col-four","Value":0}, 
     {"Target":"col-three","Value":0.571}, 
     {"Target":"col-two","Value":0.881}

]

  • 写回答

3条回答 默认 最新

  • dongxian3852 2018-04-12 20:39
    关注

    If you have an array that defines the sort order, like:

    $order = ['col-one', 'col-four', 'col-three', 'col-two'];
    

    You can pass it into the usort comparison function and look up the sort index there. I think it's easier if you flip it so the text becomes the key.

    $order = array_flip($order);
    
    usort($items, function($a, $b) use ($order) {
        return $order[$a->Target] <=> $order[$b->Target];
    });
    

    If you don't flip it first, you have to array_search repeatedly instead. (Unless there's a better way I don't know of.)

    usort($items, function($a, $b) use ($order) {
        return array_search($a->Target, $order) <=> array_search($b->Target, $order);
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 java 的protected权限 ,问题在注释里
  • ¥15 这个是哪里有问题啊?