如何每次迭代两个数组中的每一个项目，而不是循环遍历PHP中动态html输入的完整循环

Question

I'm having two arrays of fields (id[], names[]) and I want to loop through one item each of the two array per time instead of looping through the complete cycle of id[] before looping through names[] using php

HTML Code

<input type="text" name="id[]" /> &nbsp; &nbsp; <input type="text" name="names[]" /></br>
 <input type="text" name="id[]" /> &nbsp; &nbsp; <input type="text" name="nmaes[]" /></br>
 <input type="text" name="id[]" /> &nbsp; &nbsp; <input type="text" name="names[]" /></br>

PHP Code

<?php
error_reporting( error_reporting() & ~E_NOTICE );
if($_POST['test']=='test')
{
    foreach($_POST['id'] as $key => $value) {
    echo "id $key = $value"."</br>";
}
foreach($_POST['names'] as $key => $value) {
    echo "names $key = $value"."</br>";
}


}

?>

Thanks.

Answer 1

You can count number of element and use it to get your posted data. It's not really nice but that should work.

Warning, id and name need to be same size!

if($_POST['test']=='test')
{
    $count = count($_POST['id']);
    for ($i=0;$i<$count;$i++) {
        $id = $_POST['id'][$i];
        $name = $_POST['name'][$i];
        echo "id $i = $id"."</br>";
        echo "name $i = $name"."</br>";
    }
}

Other way

if($_POST['test']=='test')
{
    foreach ($_POST['id'] as $i => $id) {
        $name = $_POST['name'][$i];
        echo "id $i = $id"."</br>";
        echo "name $i = $name"."</br>";
    }
}