仅显示数组元素（如果它存在于另一个数组中）

Question

I have two array:

$array_1 = array
(
    0 => 12,
    1 => 14,
    2 => 18
);

$array_2 = array
(
    0 => 13,
    1 => 14,
    2 => 22
);

I need only elements which is present in both array. I've tried array_intersect but didn't get desired output.

$result = array_intersect($array_1, $array_2);
$result = !empty($result);
print_r($result);

It is giving output 1 instead of 14.

Answer 1

Your code is perfectly fine.

Just remove the line:

$result = !empty($result);

empty() returns TRUE or FALSE only not the actual value of the variable's value.

OR,

Change the above line to:

$result = ! empty($result) ? $result : NULL;