sum和divide取决于输入php

Question

I have a form like this

for($x=0;$x<8;$x++){
 echo "<input name='test[]'> <br>";
}

then i'm input, and i get this result

Array
(
    [0] => 1
    [1] => 2
    [2] => 0
    [3] => 0
    [4] => 0
    [5] => 
    [6] => 0
    [7] => 
)

I want to sum then divide it. I'm using array_sum to sum it. Now the problem, how can i divide it depends on my input(s) not the many of input field(s) and i don't want count the zero as input.

so it will become something like this

(1+2) / 2

how can i achieve that? sorry for my bad english.

Answer 1

If you want only non-zero values to be counted, you'll need to filter those zero and empty values away. You can still use array_sum(), to sum the array, but you'll need a filter on your count(), because count() will count all elements, regardless of the content (except null-values).

array_filter() takes care of this. So you'll simply need this

echo array_sum($myArray) / count(array_filter($myArray)); // Outputs 1.5 with your sample-array

Live demo

• http://php.net/count
• http://php.net/array_filter