duanjing2013 2014-10-24 07:40
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php函数将结果返回到数组变量中

I have 2 files named login.php and configDb.php . I have a function named sql_query($query) in configDb.php somehow like this:

function sql_query($query) {
$link=mysqli_connect("localhost", "root", "", "basheer");
if (mysqli_connect_error()) {
    echo mysqli_connect_errno();
}
$q=  mysqli_query($link, $query);
while ($row=mysqli_fetch_array($q))
{   
       return $row['username']." ".$row['password'];
}
}

I included file in login.php and I am able to fetch the result in an array variable:

$username = $_POST['user'];//
$password = $_POST['pass'];
$query="select * from tbladmin where username='Admin'";//Sql query
require  'include/config_db.php';
$user=  sql_query($query);//passed the function result to an array var
print_r($user);//prints the result correctly
echo '<br/>';
if ($username == $user['username'] && $password == $user['password'])
//I am stuck here with $user['username] and $user['password'] 
{
   header("location: index.php");
} else {
    $message = "Invalid user name or password, please try again!";
}

How to compare $username and $password with $user array variable ?

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  • douliao8760 2014-10-24 07:46
    关注

    Make your function return an array instead of a string

    Change:

    return $row['username']." ".$row['password'];
    

    To:

    return array("username" => $row['username'], "password" => $row['password']);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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