输入日期并在将来给出日期

Question

I am letting a user input a date. How should I return a date from their input and add 3 years to it? I tried to use mktime and date but it did not work out very well.

$input_date = 2010-03-28

My solution currently is just basic math for a given date 3 years ahead.

$input_date = $input_date + 3000;

Let's say I would want to give a date 4 years and 4 months 10 days

$future_date1 _datum = mktime(0, 0, 0, date("m")-2, date("d"),   date("Y")+3);
$future_date2 = mktime(0, 0, 0,     date("m"), date("d"),   date("Y")+3);

Answer 1

You can use strtotime('+ 3 years') or DateInterval for an object oriented approach.