使用php从包含数值的字符串中删除前导零和尾随零

Question

I'm trying to trim the leading and trailing zeros from a string that contains a numeric value used to represent a percentage.

I wrote this ugly block of code that combines rtrim(), ltrim() with a preg_replace():

rtrim(ltrim(preg_replace("/\d*\.(0(?![0$])|[1-9])*\K0+$/", "", $value),"0"), ".")

But it doesn't seem to work since if I enter 0010.003000 the output is 10.003000 instead of the desired 10.003

Is there a way to make a regex read right to left in Php (delete zeros from the right until you find a zero or a [1-9])? Or is there a way to improve my regex to accomplish my goal?

Important note: For some arguable reason I can't do a simple cast to float and simply enjoy the time saved playing videogames.

To better explain my strange question here are some samples with expected behaviors: 01.00 => 1 , 100 => 100 , 002.0050 => 2.005 , 0.005 => .005

Answer 1

Try the following:

/^0+|\..+?\K0+$/g

This either matches one or more 0s at the start-of-string ^0+, or it matches one or more 0s at the end-of-string 0+$.

In PHP:

preg_replace_all("/^0+|\..+?\K0+$/", "", $value)

NOTE: I would recommend using the non regular expression solutions because they are more suitable for this simple situation. Nevertheless I posted this because you asked for a regular expression.

Regex101 Demo