dprlv04662 2013-10-19 16:06
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PHP if语句返回相同的值

My code is always returning true when I'm comparing these variables. What am I doing wrong?

<?php
    $postuser = (integer)bp_activity_user_id();  //echos 1int(0)
    $posteduser = (integer)bp_activity_comment_user_id();  //echos 3int(0)

    if ( $postuser === $posteduser) {
       echo 'true';
    } else {
       echo 'false'; 
    }
?>
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  • dpd2349 2013-10-19 16:15
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    You need to use the function that RETURNs the value, not outputs it.

    From docs I found for whatever this is,

    bp_activity_user_id() X-Ref Output the activity user ID.

    bp_get_activity_user_id() X-Ref Return the activity user ID.

    return: int The activity user ID.

    The function you are using echoes the variable, NOT returns it and therefore you can't set a variable with that function. Same for the this function.

    bp_activity_comment_user_id() X-Ref Output the ID of the author of the activity comment currently being displayed.

    bp_get_activity_comment_user_id() X-Ref Return the ID of the author of the activity comment currently being displayed.

    return: int|bool $user_id The user_id of the author of the displayed

    To use in an assignment, the function has to return a value. That's why your values are always (int)0: the functions you are using have no return value. So, it returns null which is cast to 0.

    <?php
      $postuser = bp_get_activity_user_id();  
    
      $posteduser = bp_get_activity_comment_user_id(); 
    
    //no need to cast: these functions return integers
    
    
         if ( $postuser === $posteduser) {
            echo 'true';
            } else {
            echo 'False'; 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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