doudiejian5827 2013-10-21 17:05
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使用php和mysql仅显示数据库中的内容一次

I'm trying to show images with a specific subject on the screen. I have 5 images with the same subject and it only shows one image. If I change the subject of the image in the database, the next image with the subject I try to call appears.

function selectSubject($subject){
        $showSubject = mysql_query("SELECT name FROM images WHERE subject = '$subject'");
        while($showSubject = mysql_fetch_array($showSubject)){
                $source_subject_trees = $showSubject['name'];
                echo "<img class=\"subject_images\" src='img/$source_subject_bomen'></>";
        }
    };
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  • dongyu9894 2013-10-21 17:07
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    mysql_query() returns a result handle. You then stomp all over that handle by re-assigning to it within your while() loop:

    $showSubject = mysql_query(...);
    
    while($showSubject = msyql_fetch_array($showSubject)) {
          ^^^^^^^^^^^^---here
    

    mysql_fetch_array() returns an array of one row's data. Since you're assigning to the SAME variable as you stored the actual query result handle, you destroy the result handle... and end up being unable to fetch any more data, because the handle's gone.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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