dthok9648 2012-10-01 21:55
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将另一个表中的数据添加到另一个表的循环中

I'm trying to add a column from an other table to a while loop from an other table, and I tried something like this but doesn't seems to work. How can I achieve something like this? As far as I understand I need to save the variables from data_auth in a array but how do I echo them withing the loop ?

$SQL = mysql_query("SELECT * FROM users ORDER BY data_reg DESC LIMIT $offset, $rowsperpage");
while($rand = mysql_fetch_assoc($SQL)){
      $id = $rand['id'];            
      $user= $rand['user'];

      $SQL2 = mysql_query("SELECT data_auth FROM access_log WHERE user = '$user'");
      while($rand = mysql_fetch_assoc($SQL2)){
            $data_auth = $rand['data_auth'];
      }

      ?>
      <li><?php echo "$user"; ?></li>
      <li><?php echo "$data_auth"; ?></li>
      <?php  
      }
      ?>
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  • dopgl80062 2012-10-01 22:04
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    As I understand - you just want to show a list of all data_auth values in a column related to user. Simplest way is:

    $SQL = mysql_query("SELECT * FROM users ORDER BY data_reg DESC LIMIT $offset, $rowsperpage");
    while($rand = mysql_fetch_assoc($SQL)){
          $id = $rand['id'];            
          $user= $rand['user'];
    
          $SQL2 = mysql_query("SELECT data_auth FROM access_log WHERE user = '$user'");
    
          ?>
          <li><?php echo "$user"; ?></li>
          <li><?php          
                  while($rand2 = mysql_fetch_assoc($SQL2)){
                           echo $rand2['data_auth'] . '<br/>';
                }
              ?>
          </li>
          <?php  
          }
          ?>
    

    Besides, you use of the same variable name in second while is not safe.

    Or with temporary array:

    $SQL = mysql_query("SELECT * FROM users ORDER BY data_reg DESC LIMIT $offset, $rowsperpage");
    while($rand = mysql_fetch_assoc($SQL)){
          $id = $rand['id'];            
          $user= $rand['user'];
    
          $SQL2 = mysql_query("SELECT data_auth FROM access_log WHERE user = '$user'");
          $data_auth = array();
          while($rand2 = mysql_fetch_assoc($SQL2)){
                           $data_auth[] = $rand2['data_auth'];
                }
          ?>
          <li><?php echo "$user"; ?></li>
          <li><?php  foreach($data_auth as $da){
                 echo $da . "<br/>";
               }   
              ?>
          </li>
          <?php  
          }
          ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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