我如何使这个PHP工作？

Question

I was hoping the below would print

live
got here

Instead it prints

got here

The code:

$config['env'] = 'live';

sayEnvironment();

function sayEnvironment () {

  echo $config['env'];
  echo 'got here';

}

How do I set this global variable and have everything inside a function access it?

Answer 1

Use global to use global variables inside functions:

$config['env'] = 'live';

sayEnvironment();

function sayEnvironment () {
  global $config;
  echo $config['env'];
  echo 'got here';
}

Or if you have anonymous function, you can use use:

$sayEnvironment2 = function () use ($config) {
    echo $config['env'];
    echo 'got here';
};

$sayEnvironment2(); // must be called AFTER php parser has seen actual function.

Sample