php中的日期差异自定义输出

Question

Here is my php code. It is working fine.

<?php
........
    $cdt1 = Date("Y-m-d H:i:s");            

    $last_seen = "2015-05-20 12:15:20";

    $datetime22 = new DateTime($cdt1);

    $datetime11 = new DateTime($last_seen);

    $interval1 = $datetime11->diff($datetime22);

echo $interval1->format('%y years %m months and %d days %H hours, %i min and %s sec ');
.........
?>

It is giving me output like this. 0 years 0 months 0 days 00 hours 1 min and 52 sec. Something like that.

I want

  if year is 0 then year doesn't show.
  if month is 0 then month doesn't show.
  if days is 0 then days doesn't show.
  same for hour and min as well.

e.g if difference of time is 1 hour 24 min 30 sec then it should appear like 1 hour 24 min 30 sec. I don't want year/month/days if they are 0.

Please advise.

Answer 1

One option could be using a regular expression:

$date = $interval1->format('%y years %m months and %d days %H hours, %i min and %s sec ');

$replaced = false;
while ($replaced)
{
    $date = preg_replace('/^(0 [a-z]+)/', '', ltrim($date, " ,and"), 1, $replaced);
}

Notice the ^ character showing the beginning of the regular expression, the fourth parameter to make only one replacement at a time and the fith one to use it as a bool (integer) flag in the while.