php联系表单回复发件人

Question

The following code is sending an email from my website, but the email comes from [e-mail], how do i change this to the sender's email address, which i have given the variable $email:

<?php
if(isset($_POST['submit'])) {
    $msg = 'Name: ' .$_POST['FirstName'] .$_POST['LastName'] ."
" 
    .'Email: ' .$_POST['Email'] ."
" 
    .'Message: ' .$_POST['Message'];
$email = $_GET['Email'];
    mail('[e-mail]', 'Message from website', $msg );
    header('location: contact-thanks.php');

    } else {
header('location: contact.php');
exit(0);
}
?>

Adding the header From: to my mail command seems to allow me to change the email address, but i can't work out how to do it to the variable.

Answer 1

Declare the variable in the headers..

<?php
$to      = '[e-mail]';
$subject = 'the subject';
$message = 'hello';
$headers = 'From: [e-mail]' . "
" .
    'Reply-To: [e-mail]' . "
" .
    'X-Mailer: PHP/' . phpversion();

mail($to, $subject, $message, $headers);
?>

Edit:

<?php
if(isset($_POST['submit'])) {
    $msg = 'Name: ' .$_POST['FirstName'] .$_POST['LastName'] ."
" 
    .'Email: ' .$_POST['Email'] ."
" 
    .'Message: ' .$_POST['Message'];
$email = $_GET['Email'];
$headers = 'From: '.$email."
" .
    'X-Mailer: PHP/' . phpversion();
    mail('[e-mail]', 'Message from website', $msg, $headers );
    header('location: contact-thanks.php');

    } else {
header('location: contact.php');
exit(0);
}
?>