如何将参数从JQUERY传递给PHP以更新会话变量？

Question

I am trying to pass a selection/value from a dropdown menu which was dynamically created to php file and store it in a session variable, but the php is not getting any parameter. This is my code in the Jquery file:

$('#fgdesignation').change(function ()
            {
                var project =$("#fgdesignation option::selected").text();
                var url='backend.php';
             // alert(project);
            $.post(url, {fgdname : project});

        });

and this is the php file:

if(isset($_POST['fgdname'])) {
    $fgdname= $_POST['fgdname'];
    $_SESSION['fgdname']=$fgdname;
}

Thank you!

Answer 1

Try this:

$('#fgdesignation').change(function () {
    var project = $("#fgdesignation").filter(':selected').val();
    var url = 'backend.php';
    // alert(project);
    $.post(url, {
        fgdname: project
    });
});

Off hand, I saw that you were using .text() instead of .val()

Uncomment your alert() and see if there is value being returned

EDIT I did $("#fgdesignation").filter(':selected').val(); assuming: <select id="fgdesignation'>.