在PHP中评估字符串

Question

Well. I'm having a problem with the eval(); function in PHP. I don't quite understand how to store the returned data into a variable to print.. my code is as follows:

<?php 
    $a = 4; 
    $write = eval("$a+$a;"); 
    echo $write; 
?>

I'm not sure what I'm doing wrong. When I run the PHP script, all it does is output nothing.. Any help is appreciated

Answer 1

From the PHP documentation:

eval() returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned.