doubaoguo7469 2016-03-20 17:18
浏览 20
已采纳

我如何从数组()中删除它?

How can i remove "dato" from $this->v ? And still have it in the $sql string.

OUTPUT (var_dump($this->v)):

array (size=4)
  ':kategori' => string 'Youstube' (length=8)
  ':link' => string 'http://urls' (length=11)
  ':navn' => string 'Rss feeds' (length=9)
  ':dato' => string 'NOW()' (length=5)

OUTPUT (echo $sql)

UPDATE rss_kategori SET kategori = :kategori, link = :link, navn = :navn, dato = NOW()

CODE:

$classVars = get_class_vars(get_class($this));
            $sql .= "UPDATE {$this->table} SET ";
            foreach ($classVars as $key => $value) {
                if ($key == 'v' || $key == 'db' || $key == 'id' || $key == 'table' || $key ==
                    'table_id') {
                    continue;
                }
                $keys = "";
                $values = "";
                $keys .= $key;
                if ($this->$key == 'NOW()') {
                    $values .= $this->$key . ",";
                } else {
                    $values .= ":" . $key . ",";
                }
                $this->v[":" . $key] = $this->$key;
                $sql .= "{$keys} = " . $values . " ";

            }

            $sql = substr($sql, 0, -2) . " WHERE {$this->table_id} = '{$this->id}'";
  • 写回答

2条回答 默认 最新

  • dqd78456 2016-03-20 17:29
    关注

    Please try this:

    $key = ':dato';
    $arr = $this->v;
    if (array_key_exists($key, $this->v) {
         unset($arr[$key]);
         $this->v = $arr;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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