dsgdfh302506 2016-02-26 11:39
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使用CodeIgniter访问jQuery中的PHP变量[重复]

This question already has an answer here:

I have the following defined in my controller:

$data['is_amazon'] = $product->is_amazon;
$data['is_ebay']   = $product->is_ebay;

Directly below this in the controller I'm calling a .js file (jQuery).

$this->template->add_js('js/is_ebay_amazon_prouct_edit.js');

I'd like to access these php variables in my jQuery script, I've tried this approach:

var amazon = '<?php echo $is_amazon; ?>';
var ebay = '<?php echo $is_ebay; ?>';


jQuery(document).ready(function($) {

    alert(amazon);
    //alert(ebay);

});

Although this just displays my physical text in the alert, I.E:

<?php echo $is_ebay; ?>

What is the best approach here in terms of making these variables accessible in my jQuery?

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  • douyan1896 2016-02-26 11:45
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    Try this

    do one thing.. you need to create two input hiddent field in view. like this

    <input type='hidden' id="amazon" value="<?php echo $is_amazon; ?>" />
    <input type='hidden' id="ebay" value="<?php echo $is_ebay; ?>" />
    

    and call that value in you jquery lik this

    $(document).ready(function() {
    
        //alert($('#amazon').val()+" "+$('#ebay').val());   
    
         console.log("amazon"+$('#amazon').val());
         console.log("ebay"+$('#ebay').val());    
    });
    

    now it will work for u.. try it.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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