doukuiqian9911 2015-09-12 06:43
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在codeigniter中使用数据库创建下拉列表

Hi I am trying to create a dropdown using a CI forms. I have a table reseller and in that i have a field called Key. Now I have another table Users where i store user's information. I want to create a new user and in that user creation form i have a drop down field called Key where i want to fetch the key of all the resellers. So that i can identify which user is mapped to which reseller using that key.

For Controller I have done this :

$data = $this->user_m->array_from_post(array('sip_id','sip_pass','name','key','email', 'password','phone','status','created','balance'));


                $this->load->model('reseller_m');

                $this->data['resellers'] = $this->reseller_m->get('key');

                $data['password'] = $this->user_m->hash($data['password']);




                $key=$this->user_m->save($data, $id);
                redirect('admin/user');


                }

                $this->data['subview'] = 'admin/user/add';
                $this->load->view('admin/_layout_main', $this->data);

The View is

<tr>
    <td>Key</td>
    <?php if(count($resellers)): foreach($resellers as $reseller) ?>
    <td><?php echo form_dropdown('key', set_value('key', $user->key));?></td>
</tr>

But i dont get anything on screen. So How to create this drop-down?

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1条回答 默认 最新

  • duannian4784 2015-09-12 07:42
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    Can you please try it like this:

        <tr>
            <td>Key</td>
            <?php if(count($resellers) > 0) {
                      foreach($resellers as $reseller) { ?>
                      <td>
                          <?php echo form_dropdown('key', set_value('key', $user->key));?>
                      </td>
                     <?php } 
                     } ?>
        </tr>
    

    Is this variable right: $user->key? I think you need to use: $reseller->key.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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