2015-09-12 11:33
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I got 4 errors while running this code that add the email address of the user to the database called ecommerce in the table called subscriptions.

$con = new mysqli('localhost', 'root', '','ecommerce');

if (!$con) {
    die('Could not connect: ' . mysql_error());

$errors = array();
            $errors['email1'] = "<p style='color:red;font-family: BCompset, Arial, Helvetica, sans-serif;font-size:30px;float:right;'>Dont forget to write your email!</p>";
        }else {
            $email = test_input($_POST["email"]);

            // check if e-mail address is well-formed
            if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
                $errors['email2'] = "<p style='color:red;font-family: BCompset, Arial, Helvetica, sans-serif;font-size:25px;float:right;'>Something wrong is with your email</p>"; 

                // check if the email already exists
                $query = mysqli_query("SELECT * FROM subscriptions WHERE email='$email'");
                if(mysqli_num_rows($query) > 0){
                    $errors['email3'] = "<p style='color:red;font-family: BCompset, Arial, Helvetica, sans-serif;font-size:25px;float:right;'>Your had been registered before!</p>";

        //check errors
        if(count($errors) == 0)
            $insert_email = mysqli_query("INSERT INTO subscriptions (email) VALUES ('$email')");
            $insert_email = mysqli_query($con, $insert_email);
            $success = "<script>alert('Your email was successfully added to our database!')</script>";

function test_input($data) {
   $data = trim($data);
   $data = stripslashes($data);
   $data = htmlspecialchars($data);
   return $data;
<form action="" method="POST" class="searchform" dir="ltr">
                                <input type="text" name="email" placeholder="Your email address" value="<?php if(isset($_POST['email'])) echo $_POST['email']; ?>"/>
                                <button name="submit" type="submit" class="btn btn-default"><i class="fa fa-arrow-circle-o-right"></i></button>
                                <p><?php if(isset($errors['email1'])) echo $errors['email1']; ?></p>
                                <p><?php if(isset($errors['email2'])) echo $errors['email2']; ?></p>
                                <p><?php if(isset($errors['email3'])) echo $errors['email3']; ?></p>
                                <p><?php if(isset($success)) echo $success; ?></p>
                                <?php if(count($errors) == 0){echo "<p id='para' dir='rtl'>You can add your email to our emailsshow list.</p>";}?>

The errors are like this:

Warning: mysqli_query() expects at least 2 parameters, 1 given on line 27

Line 27:

$query = mysqli_query("SELECT * FROM subscriptions WHERE email='$email'");

Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, null given on line 28

Line 28:

if(mysqli_num_rows($query) > 0){

Warning: mysqli_query() expects at least 2 parameters, 1 given on line 37

Line 37:

$insert_email = mysqli_query("INSERT INTO subscriptions (email) VALUES ('$email')");

Warning: mysqli_query(): Empty query on line 38

Line 38:

$insert_email = mysqli_query($con, $insert_email);

I'm new at this forum and it would best if you can help me with that cause I really do know to do ... thanks in advance!

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3条回答 默认 最新

  • douwaif22244 2015-09-12 11:42

    Instead of

    $query = mysqli_query("SELECT * FROM subscriptions WHERE email='$email'");


    $query = $con->query("SELECT * FROM subscriptions WHERE email='$email'");


    $query = mysqli_query($con, "SELECT * FROM subscriptions WHERE email='$email'");

    Also instead of

    $insert_email = mysqli_query("INSERT INTO subscriptions (email) VALUES ('$email')");


    $insert_email = $con->query("INSERT INTO subscriptions (email) VALUES ('$email')");

    These are the only 2 errors that I could see.

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