如何查看变量，在ajax中运行其他文件脚本

Question

Example: I have file ajax demo_ajax.php will return:

<p>this is data in file ajax</p>
<script>
   demo();
</script>

And file script demo_script.js :

$(document).ready(function(){
  function demo(){
  // my code here
  }
});

My question is how to in file demo_ajax.php can call function demo() in file demo_script.js, I will try and get error function undefined

Answer 1

Change

$(document).ready(function(){
  function demo(){
  // my code here
  }
});

To

$(document).ready(function(){

}); 
  function demo(){
  // my code here
  }

Dont't forgot to include your script file on parent page