Ajax / Jquery与PHP通信

Question

I am completely new to Ajax (Jquery POST), and I wrote this thing to try to "talk" to a .php file:

function send(d){
    $.post("http://somesite.net/read.php",{data:d})
    .done(function(data){
        document.getElementById('res').innerHTML=data;
    });
}

Read.php:

$d=$_POST["d"];
echo $d;

So, it does return stuff, but it seems like it returns the entire file. It is very likely I am doing something incredibly wrong. I would like to know what it is.

Answer 1

It should be:

$d=$_POST["data"];
echo $d;

See this line:

{data:d}

You are sending variable data with a value d. So in your backend, you should request for variable name.