duanqiao1961 2013-12-04 11:35
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Wordpress php else if语句带有高级自定义字段

I'm trying to make an if-else-statement which works by going if there is a link print it around the name.

I have the below code which is almost there. However, the link is being printed above the text ranther than being an actual link.

<?php if( the_sub_field('corporate_link') ){ ?>

<a href="<?php the_sub_field('corporate_link'); ?>" 
   target="_blank" 
   title="<?php the_field('corporate_name'); ?>"><?php the_field('corporate_name'); ?></a>

<?php } else { ?>

<?php the_sub_field('corporate_name'); ?>

<?php } ?>

Any thoughts on how to make it link instead of printing the link if it`s there?

So what im looking to acheive is if there is a link print this

 <a href="<?php the_sub_field('corporate_link'); ?>">Coprate Name</a>

If there isn't a link it just shows the corporate name.

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2条回答 默认 最新

  • doukun8944 2013-12-04 11:57
    关注

    use get_sub_field('corporate_link') instead of the_sub_field('corporate_link')

    <?php 
       $corporate_link = get_sub_field('corporate_link');
       $corporate_name = get_sub_field('corporate_name');
    
      if( $corporate_link != '' ){ ?>
    
       <a href="<?php echo $corporate_link; ?>" 
       target="_blank" 
       title="<?php echo $corporate_name; ?>"><?php echo $corporate_name; ?></a>
    
     <?php } else { ?>
    
     <?php echo $corporate_name; ?>
    
    <?php } ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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