douqinlu4217 2015-02-25 10:30
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Cakephp:如何从Google App Engine中检索视频网址

Uploading Video:

require_once 'google/appengine/api/cloud_storage/CloudStorageTools.php';  
use google\appengine\api\cloud_storage\CloudStorageTools;

$gs_name = $file1['tmp_name'];
move_uploaded_file($gs_name, 'gs://bucketname/videos/' . $file_name);

Fetching Video:

$file_url = CloudStorageTools::getPublicUrl("gs://bucketname/videos/20150225074324830.mp4", true);

I am not able to fetch the video, please let me know how to fetch the video from Google App Engine. Successfully fetched the images from google app engine by :

$image_url = CloudStorageTools::getImageServingUrl('gs://bucketname/avatars/' . $user['User']['id'] . '/' . $user['User']['avatar']);  
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  • douke7431 2015-02-25 12:30
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    I resolved the issue, code to fetch the video is:

    $file_url = CloudStorageTools::getPublicUrl("gs://bucketname/videos/20150225074324830.mp4", true);
    

    Problem is that I have to mark the video as public by writing following code:

    $storeAt="gs://bucketname/videos/20150225074324830.mp4";
    $options = array('gs'=>array('acl'=>'public-read','Content-Type' =>   $file['type']));
    $ctx = stream_context_create($options);
    $saved = file_put_contents($storeAt, file_get_contents($file['tmp_name']), 0, $ctx);
    

    enter image description here

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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