仅使用php从一个php文件请求信息到另一个

Question

I am pretty new to php so I'm having trouble with POSTing. I am trying to transfer information between 2 php files where send_var.php sends a command by POST and get_var.php executes some data manipulation and returns the response. The send_var.php is as follows:

<?php
$url = "./get_var.php";
$fields = array('response' => "323243");
$data = http_build_query($fields);
// echo $data."<br />";

$context = stream_context_create(array(
    'http' => array(
    'method'  => 'POST',
    'header'  => "Content-type: text/html
",
    'content' => $data
),
));
$out = file_get_contents($url, false, $context); 
echo "Info from get_var : " . $out;
?>

And the get_var.php is :

<?php
$arg1 = isset($_POST['response']) ? $_POST['response'] : null;
if($arg1 == '')
    {
    echo "No Command! ";
    }
if($arg1 != "")
    {
    echo $_POST['response'];
    }
else
    {
    $_POST['response'] = "123456";
    echo $_POST['response'] . " end of get_var";
    }
?>

This code was extracted from other examples on stack overflow. The only output I get is "Info from get_var :" Obviously I'm missing some pretty fundamental knowledge. If someone can help it would be much appreciated. I'm executing this under XAMPP.

Answer 1

In order to run a PHP script, you have to access it through the webserver. So the URL needs to be an http: URL, not just a filename:

$url = "http://localhost/path/to/get_var.php";

If you just use a filename, file_get_contents() will just return the PHP source code, it won't run it.

Also, your Content-type header is wrong, it should be application/x-www-form-urlencoded, not text/html (that's the content type of the response, your context specifies the type of the POST data).