duanmu8911 2014-05-14 22:28
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如何正确使用视图中的关联?

I want to make simple output. This is part of list.phtml:

// more code
<td>
    <a href="<?=$this->url('news', array('action'=>'full', 'id' => $item['id']));?>"><?=$item['title'];?></a> 
</td>
<td>
    <?=$item['category']->getName();?>
</td>
<td>
    <?=$item['user']->getDisplayName();?>
</td>
// more code

As you see I am outputting name in a tag, category name and user name. I am working with models, so $item['category'] is object of class Category and $item['user'] is object of class User.

The question is it correct get values this way or should I do it in controller or somehow else?

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1条回答 默认 最新

  • dongpenggan6812 2014-05-15 00:18
    关注

    Instead of passing the entire object to your view and calling its methods there, return an array in your controller action that has the exact view variables that you will need to use in your view file.

    Like this:

    class FooController extends FooClass
    {
        public function listAction()
        {
            // do stuff
    
            // setting view variables
            return array(
                'category_name' => $your_object->getName(),
                'display_name'  => $your_object2->getDisplayName()
            );
        }
    }
    

    That way in your view file all you have to do is:

    <td>
        <?php echo $this->category_name;?>
    </td>
    <td>
        <?php echo $this->display_name;?>
    </td>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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