<?php
if (isset($_POST['submitted'])){
include('connect.php');
$name=$_POST['name'];
$addr=$_POST['addr'];
$phno=$_POST['phno'];
$tr=$_POST['tr'];
$trd=$_POST['trd'];
$sname=$_POST['sname'];
$sphno=$_POST['sphno'];
$sfield=$_POST['sfield'];
$med=$_POST['med'];
$apaid=$_POST['apaid'];
$apend=$_POST['apend'];
$sqlinsert="INSERT INTO patient (name , addr , phno , tname , tdate , sName , sphno , sSpeciality , med , amtpaid , amtrem) VALUES
('$name','$addr','$phno','$tr','$trd','$sname','$sphno','$sfield','$med','$apaid','$apend')";
if(!mysql_query($dbcon , $sqlinsert))
{
die('error inserting new record');
}
else
echo "new";
}
?>
<html>
<head>
<title>Insert Data</title>
</head>
<body>
<h1>Insert Data</h1>
<form method="post" action="insert.php">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>New Patient</legend>
<label>Name : <input type="text" name="name" /></label>
<label>Address : <input type="text" name="addr" /></label>
<label>Phone no : <input type="text" name="phno" /></label>
<label>Treatment : <input type="text" name="tr" /></label>
<label>Treatment date : <input type="text" name="trd" /></label>
<label>Specialist Recommended : <input type="text" name="sname" /></label>
<label>Specialist phno : <input type="text" name="sphno" /></label>
<label>Specialist field : <input type="text" name="sfield" /></label>
<label>Medicine : <input type="text" name="med" /></label>
<label>Amount Paid : <input type="text" name="apaid" /></label>
<label>Amount Pending : <input type="text" name="apend" /></label>
</fieldset>
<br />
<input type="submit"value="add new record" />
</form>
</body>
</html>
i m getting this error while inserting even when the table has a string variable
Warning: mysql_query() expects parameter 1 to be string, object given in C:\xampp\htdocs\insert.php on line 18 error inserting new record
please help...
