带引号的意外T_CONSTANT_ENCAPSED_STRING [已关闭]

Question

Can someone help me to find what is wrong in the $secret line ?

$secret should give :

{"name":"JustAname","extra":"1","password":"ASD123","report":"http:\/\/website.com\/dev\/gamereport\/0001.php"}

here's the PHP code:

<?php
date_default_timezone_set('America/Montreal');
    $name = 'JustAname';
    $extra = '1';
    $password = 'ASD123';
    $reception = 'http:\/\/website.com\/dev\/gamereport.php';
    // Code de génération de la base64
    $secret = '{"name":"'.$name'","extra":"'.$extra'","password":"'.$password'","report":"'.$reception'"}';
    $encodedSecret = base64_encode($secret);


    $tournementLink = 'pvpnet://lol/customgame/joinorcreate/map1/pick6/team5/specALL/'.$encodedSecret;

    echo $tournementLink;
?>

I got: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in [...] on line 20

Answer 1

You're incorrectly concatenating strings, as @hobbs suggests. You're also using the undefined variable $Tournament, which I think should be $name. Try this:

$secret = '{"name":"' . $name . '","extra":"' . $extra . '","password":"' . $password . '","report":"' . $reception . '"}';

On a side note, a slightly nicer way to create JSON in PHP is to use an array and json_encode():

$secret = json_encode(array(
        'name' => $name,
        'extra' => $extra,
        'password' => $password,
        'report' => $reception));