在PHP代码中单击链接javascript函数调用

Question

<?PHP 
$result = mysql_query($query);
$finalval=0;
while($row = mysql_fetch_array($result))
{
$finalval=$finalval."<a onClick='showContent("please display")' 
href='#' >".  $row['Title']   ."</a> <br>" ;
}
echo  $finalval;
 ?>

    <script language="javascript" type="text/javascript"  >

function showContent(value)
{
alert value;

}
</script>

Guys please help me out and please please tell me in a php code on clicking link how to call javascript/ajax function..Thank you so much

Answer 1

Try this one ,opening double quotes within double quotes you need to escape them \

$finalval=$finalval."<a onClick='showContent(\"please display\")' 
href='#' >".  $row['Title']   ."</a> <br>" ;
}