PHP可以将命名空间扩展为本机使用类外的函数

Question

Okay here is the scenario:

Here are two example classes.

1. The first one defines some functions outside the class name.
2. I would like the second class to be able to implement it as if it was defined natively.

There are a couple of functions I use a lot.

I thus need them to be as short as possible for readability and writing speed.

If i could stick them in a namespace and extend it in some way, it would also prevent possible conflicts in other libraries.

Base class

namespace Core;

class Base{
  ......
}

function set($array, $path=null, $value=null){
  .....
}

function get($array, $path=null){
  .....
}

Second Class

namespace Core\Config;

class Config{
  public function __construct($array){
    $conf = get($array, 'key1.key2.key3');
    .... do something with returned value ....
  }
}

Answer 1

Someone suffested that already but not in the right way:

<?php
namespace Base {
    function get() {...}
}

namespace Base\Config {
    use \Base as B;

    class Config {
        public function __construct(...) {
            $something = B\get(...);
        }
    }
} 

You can import and alias the Base namespace and use it.
However, you cannot import a function or constant (only classes and interfaces)

Reference: PHP.net

---

Also note, that you cannot define a function in a class outside the class name.
What you are doing is defining a class and several "stand-alone" functions in one file, but they do not relate in an way (they are in the same namespace, though).