doufangzhang4454 2013-01-21 06:49
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file_get_contents()期望参数1为字符串,

I am trying to make an image upoad form. The following is the code for the form

<table align="center">
<form enctype="multipart/form-data" action="register.php" method="post" onsubmit="return vaidate();" >
<tr><td>
Username:</td><td><input type="text"id="user" name="user"> </td> </tr>
<tr><td>
Password:</td><td><input type="password" id="pass" name="pass" ></td></tr>
<tr><td>
Confirm Password:</td><td><input type="password" id="cpass" name="cpass" onchange="validate()" ></td><td> <div id="error"></div></tr>
<tr ><td>
Profile Picture: </td> <td> <input name="userfile[]" type="file" />
</td>
</tr>
<tr align="center"><td colspan="2">
<input id="submit" align="center" type="submit" > </td>
</form>

and the recieving php page is

if(isset($_FILES['userfile'])){

            $imgData =addslashes (file_get_contents($_FILES['userfile']));
            $query = 'INSERT INTO users (User,Password,Picure) VALUES ("'.$_POST["user"].'","'.$_POST["pass"].'","'.$imgData.' ")';
            }

        else
        {
        $query = 'INSERT INTO users (User,Password,) VALUES ("'.$_POST["user"].'","'.$_POST["pass"].' ")';
        }

but i keep getting the error

file_get_contents() expects parameter 1 to be string, array given

Any solutions please?

On the suggestion of the answers i replaced with the following

$imgData =addslashes (file_get_contents($_FILES['userfile']["tmp_name"][0]));

but now my query wont run. on printing $query i realised there is no ") at the end of the string as concatenated by the function. Any ideas?

the output of echo $query is

INSERT INTO users (User,Password,Picure) VALUES ("12312312","1122","ÿØÿà\0JFIF\0\0\0d\0d\0\0ÿì\0Ducky\0\0\0\0\0P\0\0ÿî\0Adobe\0dÀ\0\0\0ÿÛ\0„\0               ÿÀ\0\07\0Î\0ÿÄ\0©\0\0\0\0\0\0\0\0\0\0\0\0   \0\0\0\0\0\0\0\0\0\0\0\0\0\0   \0\0\0\0!1  Aa\"Q2q‘BR#bÓ–XrÒ$ð±ñ‚3CcÔ&\0\0\0\0\0\0\0!1AQaq‘¡±Ñ\"2BðÁRá²#3$ÿÚ\0\0\0?\0?gà >žâû9ÜFùw2à   Ùܧ!ÃðÊ:úKØ°¨òÉMë+:\0ô•6Oø? 8ÓqSÃ#sÀ$Õ\'¾ŽI$ÀQn½µ;NÝ\\#~¬÷v6òãÏŒuËHîGD‹ßËQ:/¢?œ9éÔ’tÔqç–¿ŽHv±ÀÔèQcnæÈ\\àEðÔ|ÿ\0ñã6œ*ê>*êýA4B@n¦smöÛ;Ïl_C1*9¶jqÍ:JØeKmùµô¤‰ƒõâUýUy7;—ÿ\0²œ    ð7ÿ\0\'¡Ìz¯ê¯ýåÜþzæS¾cùòp~<}UýT³»ZÃl°ß6—ºžýÌ|~<ˉrHó}U‡T×›:%?KK|¶žZô¤k©çÆõáÓ¸ŒpZ;v‘ªpŽ+UuUÔ8*­Ö9r<ø”UWPà(UÔ.*ëõp!WP« º‡QU~¡À…ZŽ\"¨Vë?ÇÉB® xŠ¡_QÁT*Ôxq(ZÛ›XTTö—vNˆõÔñ`ùðCÐ]qG]<’xÝĪ     %E–ÇÜ‹»—í-å×îzá@Ÿ9ù0 }²µÁ—\\*C(Rãt¡:$jxÙ&ܧò~tºi;ÜÛÍ{{È··}s\'²&î¬,gcþlxÑš‰OPÙeå Gi¡õ¾ÓÚë¯$‚=J(Ù8Ž1JȘ–’=ÑïqA~ÛÜ‹»7®®åTîƒê\'XÉ“Wu•®zhÎ8TÓ)+Œ£¢¢y“áãâKæñ6ûh[Ž©Y½–¦Ž]&«Ý}èvÆU+w\'&ÝÛg¥NÍî\"E*k’ÚÄJø,!qÅ«©kuÑÒžI^½Iæî\'IZQ d5+Ø¿xe}Sg±ïgºû9Ë°‘¿cN­]E¸“}#žº#„5§/‚tâØãíÚ)°x®.º•ßr$}‡wƒœw—Oí»¸v îž;–UIzªÆÒt¹IEœÚPÒÒ’¤©iêJ’ªéQÈØ2ݾ¬_)¯UzÎèÊv?Zo½¾ÔGzPÙœG©yï°W\0€Èêë\'ÈðHN¼%ü©Þqí)€†6ý£ÉDkyrÈYÞën_Y_¦¯!¿Ÿ*ªºAˆìCSÊÛi´è”€ØHåÆâÞ3mmkAOœ”‡8‘Õi]†Æ2j ÏÝlÓ¬ÈãI–Æ3µm    ™m 2*s%ä) ¨ºÒu^Dp‹œ¹psXÓMpLxèƒ.EÞoo; `B¦ì¾%Iq·R¥PWõ¶ABò£Ó:…òñéKzü¸bÉl˜h<ªª–\\8WÖñ¾á7מ‹ZI\'™$üx}ncnæÔÓÚ–Iy(qJsÝ}q­±²¤rØåû§ut¹   ÌnâÅôUUHi   n48q’Øy× Qqߥ#D„¬Sáü§*ë ÊÛ=*Ôú_G[ÅÛ|½y0Õ?o­ØÎ7Ÿ·ZÜÓq2ä¹I¾µ…2Ím4ºu%¤t2”\'’V>g98YÛZ((šÙHé#©)–û‡÷ážm–ãÒí.ÅåI¢³Ä›wí¦#ÊS’ä õ >‡ÓjóÑ:•-  Ôt(_ÉX_ ÀäkÛ²×ma\\ç³=ðïcº½ÎfŽnïL¨ÛŒQlÙîüjšÔ¯Ó…êÕ{+ÐRìΕ uBÜÐô„«¯!okkvüÇ!Åsµ–i]õ`œÇv^ç8–Ð[ÚíæÎÖÅÜî©Åż¾µ ZÉ  )”–T§®J )BO\"µ)*@§eÃ:aºC@tÔ®÷á†=P‰Ë{üî×1šä¹;ÉkDÛ‡ùphÍ[ Á\"2¢4Óó(ðõœ]»¯z\\ûÉ\\~¥÷ÁýÀ»´Á¬šÎíØäì …;W’¥±Ýþ•‡šÀâOψ“‹·ShÈmä­ÇuQ‡Æ½É)2žÕwz+ñˆîžÙ³ «í¹zR“ǧO‡\\Ìæ\0¸¨Ýs¢žK ¢¯ÊáDþ(¶á±×å:øç‚fÛêÆ]LBïà{Ž·í?u&6ÿ\0“c•ÁF+TºTµÜ,F| ‚©Œ^_/áâ·©pÑÓÖòM‘¨ñÞ™!˜±ÛSÒe:–£´‘ª–·¢R?IÐq¶+:4 M]ɼÇkžÞÁa(C¶N/YƒGSjÌ°³HE“€Š’d¹ËŒ… ü›ÊéR|4O§>ŒQBë‰m´©Ç^¡ •(ž@\09’uåƼù$!H×µ¿l¤Æ° ›ÝùÆÎu¸™6åXÓÊ’ûi’òzÄF›Œã^cÈZ•¢‡òútêVRó—‘ÏÛ£AóNíìWf‚\'tX!µÝÀ<êñ<^õØ•-¼ául$!r1uD©^CŠSZ¨•‘ÔI× œ®’¹Ù•NÐÙ\'ûí·]ï}¹ÒP‚P\"²º~…M¹tø+ñC1œâãÂÎvm±µO¹]ãc«‹º\"ñÞÎå£jû^ÝÜ•%›ÔÎPRHR¥Ü¨@AoN}M¥å8?à<$ã¢õgkt­|±LnŸ²2TC¹xøxxòðùq¸Yµ.žÇv×ûUÚîÒãϲY³´¨NEt•€%\\¨Î(_Í´:–ÿ\0òñ†äeõ.FU¢ÑÚ3d`v\'%•exæŽÛåymÔLs¢Ž©6×SÝK,0Òyu)J? 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1条回答 默认 最新

  • dongqieli4164 2013-01-21 06:54
    关注

    $_FILES['userfile'] is an array, you need to use indexes to access the specific file attributes:

    $_FILES["file"]["name"] - the name of the uploaded file
    $_FILES["file"]["type"] - the type of the uploaded file
    $_FILES["file"]["size"] - the size in kilobytes of the uploaded file
    $_FILES["file"]["tmp_name"] - the name of the temporary copy of the file stored on the   server
    $_FILES["file"]["error"] - the error code resulting from the file upload
    

    So use something like this:

    $imgData =addslashes (file_get_contents($_FILES['userfile']['tmp_name']));
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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