获取用户在类外定义的所有变量的列表

Question

i have something like this:

class foo
{
   //code
}

$var = new foo();
$var->newVariable = 1; // create foo->newVariable
$var->otherVariable = "hello, im a variable";  //create foo->otherVariable

i can get in class foo a list of all variables defined outside by user (newVariable, otherVariable,etc)? Like this:

class foo
{
   public function getUserDefined()
   {
      // code

   }
}

$var = new foo();
$var->newVariable = 1; // create foo->newVariable
$var->otherVariable = "hello, im a variable";  //create foo->otherVariable
var_dump($var->getUserDefined()); // returns array ("newVariable","otherVariable");

Thanks!.

Answer 1

Yes, using get_object_vars() and get_class_vars():

class A {
var $hello = 'world';
}
$a = new A();
$a->another = 'variable';
echo var_dump(get_object_vars($a));
echo '<hr />';
// Then, you can strip off default properties using get_class_vars('A');
$b = get_object_vars($a);
$c = get_class_vars('A');
foreach ($b as $key => $value) {
    if (!array_key_exists($key,$c)) echo $key . ' => ' . $value . '<br />';
}