doubian6241 2011-07-17 22:51
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动态填充下拉列表PHP MySQL

I have two Drop Down Lists, the second ones are based off which one the users selects in the first drop down. I was going to use Javascript to dynamically change the second drop down. But now here comes the problem. This information is going to be stored on a user's profile. So ideally I would like to be able to pull this information out of MySQL database and display it on a PHP page. How would I go about loading the proper dynamic menu when I populate the list from MySQl. How can I accomplish this the way I want. I dont think javascript would work in this case would it?

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  • duanci1858 2011-07-17 22:56
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    If you don't want a page refresh, then the answer is "JavaScript". Now, you have a couple of options there. Personally, I prefer to load more up front, so I keep a JSON object which outlines the possibilities and then I swap static content for static content.

    This would mean that onchange I would have something like:

    var first = document.getElementById( "id of first select" )
    var items = possibilities[ 
        first.value // you can also do things with selectedIndex and options if needs.
    ];
    
    var second = document.getElementById( "id of second select" )
    for( var i in items )
    {
        var opt = document.createElement('option');
        opt.setAttribute('value', items[ it ] );
        second.appendChild( opt );
    } 
    

    Your other option is to send data "over the wire" and get it working through AJAX. Not having room for a tutorial, I think I can safely link you to this one.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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