doutun1875 2011-07-01 23:41
浏览 47

PHP和mysql分页,next / prev链接

EDIT

To clarify I dont need to know how to do pagination, I guess Im trying to figure out how to display the next/previous link if all rows are returned. So if I want to display 20 rows per page I do a limit with 21. So I know now that there is another row to diplay, then show the next link. Yet still display 20 rows on the current page and still start off at the 20th row in the next page. The current issue is if I had 0-19 on the first page, the next page would show 21-40, so its missing 20. I guess I just need to minus 1 on top of the offset to get the correct starting point.

  • 写回答

1条回答 默认 最新

  • dongzhuzhou4504 2011-07-01 23:45
    关注

    You want something like this:

     $lowerLimit = ($pageNumber - 1) * $resultsPerPage;
     $sql = "SELECT * FROM tbl1 LIMIT $lowerLimit, $resultsPerPage";
    
    评论

报告相同问题?

悬赏问题

  • ¥15 winform的chart曲线生成时有凸起
  • ¥15 msix packaging tool打包问题
  • ¥15 finalshell节点的搭建代码和那个端口代码教程
  • ¥15 用hfss做微带贴片阵列天线的时候分析设置有问题
  • ¥15 Centos / PETSc / PETGEM
  • ¥15 centos7.9 IPv6端口telnet和端口监控问题
  • ¥120 计算机网络的新校区组网设计
  • ¥20 完全没有学习过GAN,看了CSDN的一篇文章,里面有代码但是完全不知道如何操作
  • ¥15 使用ue5插件narrative时如何切换关卡也保存叙事任务记录
  • ¥20 海浪数据 南海地区海况数据,波浪数据