在PHP中使用非常困难的结果

Question

$content is an arry. when i print_r($content) the result is too long. now i

echo $fenlei=$content['body']['#object']->field_fenlei['zh-hans'][0]['taxonomy_term']->name;

the result of $fenlei is java. but there maybe many values of $fenlei. eg:

$content['body']['#object']->field_fenlei['zh-hans'][0]['taxonomy_term']->name;
$content['body']['#object']->field_fenlei['zh-hans'][1]['taxonomy_term']->name;
$content['body']['#object']->field_fenlei['zh-hans'][2]['taxonomy_term']->name;
......

how to loop out the

  $content['body']['#object']->field_fenlei['zh-hans'][1]['taxonomy_term']->name;
    $content['body']['#object']->field_fenlei['zh-hans'][2]['taxonomy_term']->name;

value. it too hard for me. :)

Answer 1

You can store the common code and foreach next:

$common = $content['body']['#object']->field_fenlei['zh-hans'];

foreach($common as $key => $value){
    echo "{$key}: " . $value['taxonomy_term']->name;
}