douxun4860 2010-11-13 18:58
浏览 16

PHP:如果没有行

if ( $bid != $USER OR mysql_num_rows($already) > 0) {
    echo "ok";
}

I have this line. I want "ok" to show, if $bid isn't the same as $USER OR if there doesn't exists any rows in the $already query.

What have I done wrong?

function show_block_Form($bid, $id, $USER){
$already = mysql_query("SELECT * FROM users_blocked WHERE bID = '$bid' AND uID = '$USER'") or die(mysql_error());
if($bid != $USER || mysql_num_rows($already)==0){
echo "ok"
}
}
  • 写回答

2条回答 默认 最新

  • dpg76975 2010-11-13 19:01
    关注

    I want ok to show, if $bid isnt the smae as $USER *and* if there doesnt exists any rows in the $already query.

    if($bid != $USER && mysql_num_rows($already) <= 0){
    
    评论

报告相同问题?

悬赏问题

  • ¥15 mmocr的训练错误,结果全为0
  • ¥15 python的qt5界面
  • ¥15 无线电能传输系统MATLAB仿真问题
  • ¥50 如何用脚本实现输入法的热键设置
  • ¥20 我想使用一些网络协议或者部分协议也行,主要想实现类似于traceroute的一定步长内的路由拓扑功能
  • ¥30 深度学习,前后端连接
  • ¥15 孟德尔随机化结果不一致
  • ¥15 apm2.8飞控罗盘bad health,加速度计校准失败
  • ¥15 求解O-S方程的特征值问题给出边界层布拉休斯平行流的中性曲线
  • ¥15 谁有desed数据集呀